File:VFPt capacitor-square-plate.svg

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Summary

Description
English: Accurately computed electric field of simple parallel plate capacitor. The capacitor consists of two square plates with plate size a and distance d=a/3. The field is accurately computed for a uniform charge distribution on each plate, but therefore the potential on each plate is not exactly constant.
Date
Source Own work
Author Geek3
Other versions

Slightly different field configurations:

SVG genesis
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 The SVG code is valid.
 This plot was created with VectorFieldPlot
Source code
InfoField

Python code

# paste this code at the end of VectorFieldPlot 2.0
doc = FieldplotDocument('VFPt_capacitor-square-plate', width=800, height=600, commons=True)
l = 4.5
d = 1.5
plates = [{'x0':-l/2., 'y0':d/2., 'x1':l/2., 'y1':d/2., 'Lz':l, 'Q':1.},
          {'x0':-l/2., 'y0':-d/2., 'x1':l/2., 'y1':-d/2., 'Lz':l, 'Q':-1.}]
field = Field([['charged_rect', plates[0]], ['charged_rect', plates[1]]])

def startpath(t):
    # take an oval with stright lines and half-cirles around one plate
    tt = (t%1) * (2 * l + pi * d)
    if tt <= l*0.5:
        return sc.array([tt, d])
    elif tt <= l*0.5 + pi/2.*d:
        phi = (tt - l*0.5) / (d/2.)
        return sc.array([l*0.5 + d*0.5*sin(phi), d*0.5 + d*0.5*cos(phi)])
    elif tt <= l*1.5 + pi/2.*d:
        return sc.array([l - (tt - pi/2.*d), 0.])
    elif tt <= l*1.5 + pi*d:
        phi = (tt - l*1.5) / (d/2.)
        return sc.array([-l*0.5 + d*0.5*sin(phi), d*0.5 + d*0.5*cos(phi)])
    else:
        return sc.array([tt - (l*2. + pi*d), d])

nlines = 22
p0list = Startpath(field, startpath).npoints(nlines)

# plot field lines
for p0 in p0list:
    line = FieldLine(field, p0, directions='both')
    doc.draw_line(line, arrows_style={'dist':2, 'min_arrows':1})

# plot capacitor plates
D = 0.055
lw = 0.01
nsign = nlines
plus = 'M 0,-0.02 v 0.04 M -0.02,0 h 0.04'
minus = 'M -0.02,0 h 0.04'
for p in plates:
    M = 0.5 * (sc.array([p['x0'], p['y0']]) + sc.array([p['x1'], p['y1']]))
    R = sc.array([p['x1'], p['y1']]) - M
    a = atan2(R[1], R[0])
    if p['Q'] > 0:
        col = '#e22'
        sign = plus
    else:
        col = '#45e'
        sign = minus
    transform = 'translate({:.6g},{:.6g})'.format(M[0], M[1])
    transform += ' rotate({:.6g})'.format(degrees(a))
    doc.draw_object('rect', {'x':-vabs(R)-lw/2., 'width':2*vabs(R)+lw,
        'y':-D, 'height':2*D,
        'style':'fill:{:s}; stroke:#000; stroke-width:{:.6g}'.format(col, lw),
        'transform':transform})
    for i in range(nsign):
        pos = M + R * (2 * (i + 0.5) / nsign - 1)
        doc.draw_object('path', {'d':sign,
        'transform':'translate({:.6g},{:.6g})'.format(*pos),
        'style':'fill:none; stroke:#000; stroke-width:{:.6g}; '.format(2*lw) +
        'stroke-linecap:square'})

doc.write()

Licensing

I, the copyright holder of this work, hereby publish it under the following licence:
w:en:Creative Commons
attribution share alike
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You are free:
  • to share – to copy, distribute and transmit the work
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Under the following conditions:
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  • share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible licence as the original.

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Electric field in simple parallel plates capacitor

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7 September 2019

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Date/TimeThumbnailDimensionsUserComment
current03:20, 8 September 2019Thumbnail for version as of 03:20, 8 September 2019800 × 600 (27 KB)wikimediacommons>Geek3User created page with UploadWizard

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